Swift iOS Pod。SimpleJSONParser 允许用户轻松地将 JSON 解析为任何 NSObject。

导入

    import SimpleJSONParser

Cocoapods

    pod 'SimpleJSONParser'

1) 这里是一个如何使用它的例子

    let dictionary = NSMutableDictionary()
    dictionary.setValue("sdfsdf", forKey: "uniqueID")
    dictionary.setValue("valera", forKey: "name")
    dictionary.setValue("34", forKey: "age")

    let dictionary2 = NSMutableDictionary()
    dictionary2.setValue(["34", "56", "876"], forKey: "ids")
    dictionary.setValue(dictionary2, forKey: "test2")


    let test = TestClass.fromJson(dictionary)

2) 测试模型

    import Foundation

    public class TestClass: NSObject {

        var uniqueID: String?
        var name: String?
        var age: Int = 0
        var test2: TestClass2?
    }

    public class TestClass2: NSObject {
        var ids: [String] = []
    }